Submission #1316358


Source Code Expand

#include<iostream>
#include<map>
#include<set>
#include<string>
#include<algorithm>
#include<cmath>
#include<vector>

using namespace std;

typedef long long ll;
typedef unsigned long long ull;
typedef int itn;

const int inf = 999999999;
const double pi = acos(-1);
const int dx[4]={1,0,-1,0};
const int dy[4]={0,1,0,-1};

#define rep(i,m,n) for(int i = (m); i < (int)(n); i++)
#define mod(i) ((i)%(ll)(1e9 + 7))
#define divm(a,b) (mod(a * modpow((ll)b,(ll)(1e9+5))))
#define rsort(a,b,c) sort(a, b, greater<c>())
#define vsort(v) sort(v.begin(), v.end());
#define ft first
#define sd second
#define pb push_back
#define it insert
#define sz(x) ((int)(x).size())
#define lb(a,n,k) (lower_bound(a,a+n,k) - a) 
#define vlb(a,k)  (lower_bound(a.begin(),a.end(),k) - a.begin())
#define YES cout<<"YES"<< endl
#define NO cout<<"NO"<<endl
#define Yes cout<<"Yes"<<endl
#define No cout<<"No"<<endl  
#define ret return

ll modpow(ll i,ll j){ ll tmp=1; while(j){ if(j%2)tmp=mod(tmp*i);i=mod(i*i);j/=2;}return tmp;}
ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
ll lcm(ll a, ll b) { return a / gcd(a, b) * b; }

///////////////////////////////////////////////////////////////////////////

int main(){
	int n;
    string s,t;
    cin >> n >> s >> t;

    rep(i,0,sz(s)){
        bool flag = 0;
        rep(j,0,sz(t)){
            if(i+j >= sz(s))break;
            if(s[i+j] != t[j]){
                flag = 1;
                break;
            }
        }
        if(flag == 0){
            cout << i + sz(t) << endl;
            return 0;
        }
    }
    cout << sz(s) + sz(t) << endl;
	return  0;
}

Submission Info

Submission Time
Task A - Prefix and Suffix
User hirata0517masato
Language C++14 (GCC 5.4.1)
Score 200
Code Size 1657 Byte
Status AC
Exec Time 1 ms
Memory 256 KB

Judge Result

Set Name Sample All
Score / Max Score 0 / 0 200 / 200
Status
AC × 3
AC × 9
Set Name Test Cases
Sample 0_00.txt, 0_01.txt, 0_02.txt
All 0_00.txt, 0_01.txt, 0_02.txt, 1_00.txt, 1_01.txt, 1_02.txt, 1_03.txt, 1_04.txt, 1_05.txt
Case Name Status Exec Time Memory
0_00.txt AC 1 ms 256 KB
0_01.txt AC 1 ms 256 KB
0_02.txt AC 1 ms 256 KB
1_00.txt AC 1 ms 256 KB
1_01.txt AC 1 ms 256 KB
1_02.txt AC 1 ms 256 KB
1_03.txt AC 1 ms 256 KB
1_04.txt AC 1 ms 256 KB
1_05.txt AC 1 ms 256 KB