Submission #953964

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Source Code Expand

/*
 * 16-10-29_AGC006_A.cpp
 *
 *  Created on: 2016/10/29
 *      Author: ryoma
 */

#include<iostream>
#include<string>

using namespace std;

int N;
string s,t;
int main(){
	cin >> N >> s >> t;
	int cnt=0;
	for(int i=1;i<=N;i++)
		if(s.substr(N-i,i) == t.substr(0,i)){
			cnt=i;
		}
	cout << 2*N-cnt<<endl;
	return 0;
}

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