Submission #1111337

---

Source Code Expand

#include <iostream>
#include <string>

using namespace std;

int N;
string A, B;

int main()
{
    cin >> N;
    cin >> A >> B;

    for (int i = N; i; -- i)
        if (A.substr(N - i, i) == B.substr(0, i)) {
            cout << 2 * N - i << '\n';
            return 0;
        }

    cout << 2 * N << '\n';
    return 0;
}

Submission Info

Judge Result